(sin^3 x-cos^3 x)/sin⁡x+cos⁡x =(csc^2 x-cot⁡x-2cos^2 x)/(1-cot^2 x)?

Update:

(sin^3 x-cos^3 x)/(sin⁡x+cos⁡x) =(csc^2 x-cot⁡x-2cos^2 x)/(1-cot^2 x)

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