Can someone please help me solve this problem, I am having trouble figuring this one out and I would greatly appreciate your help! Thank you! :)
∜(x^4 y^5 z^6 ) =
(x^4 y^5 z^6)^(1/4) =
(x^4)^(1/4) (y^5)^(1/4) (z^6)^(1/4)
|x| y^(5/4) |z|^(6/4) =
|x| y^(5/4) |z|^(3/2)
Taking a root of a number (or variable in this case) is the same as raising it to the 1/root.
So the 4th root of x^4y^5z^6 = x^(4/4)y^(5/4)z^(6/4) = x^1y^(5/4)z^(3/2) = xy^(5/4)z^(3/2)
Hope this helps!
â(x^4 y^5 z^6 )
can be rewritten
(x^4 y^5 z^6 ) ^ (1/4)
now separate each one
{ (x^4) * (y^5) * (z^6 ) } ^ (1/4)
and give each one the outside exponent
{ (x^4) ^ (1/4) } * { (y^5) ^ (1/4) } * { (z^6 ) ^ (1/4) }
and reduce
(x) * { y ^ (5/4) } * { z ^ (3/2) }
(x^4y^5z^6)^(1/4)
xy^(5/4)z^(3/2)
The fractional power postulate.
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∜(x^4 y^5 z^6 ) =
(x^4 y^5 z^6)^(1/4) =
(x^4)^(1/4) (y^5)^(1/4) (z^6)^(1/4)
|x| y^(5/4) |z|^(6/4) =
|x| y^(5/4) |z|^(3/2)
Taking a root of a number (or variable in this case) is the same as raising it to the 1/root.
So the 4th root of x^4y^5z^6 = x^(4/4)y^(5/4)z^(6/4) = x^1y^(5/4)z^(3/2) = xy^(5/4)z^(3/2)
Hope this helps!
â(x^4 y^5 z^6 )
can be rewritten
(x^4 y^5 z^6 ) ^ (1/4)
now separate each one
{ (x^4) * (y^5) * (z^6 ) } ^ (1/4)
and give each one the outside exponent
{ (x^4) ^ (1/4) } * { (y^5) ^ (1/4) } * { (z^6 ) ^ (1/4) }
and reduce
(x) * { y ^ (5/4) } * { z ^ (3/2) }
(x^4y^5z^6)^(1/4)
xy^(5/4)z^(3/2)
The fractional power postulate.