Verified answer

9^(log(base 3)20) =

(3^2)^(log(base 3)20) =

3^(2log(base 3)20) =

3^(log(base 3)(20^2)) =

20^2 =

400

So 9 = 3^2, so

9^(log₃20) = 3^2(log₃20)

using properties of logs, move the 2 as an exponent

3^(log₃20)^2

now using properties of logs, simplify the 3^log₃20 into 20

so your answer is 20^2 or 400

400 is the answer

9^(log₃20)

(3^(log₃20))^2

(20)^2

400

remember that a raised to the log base a of b is equal to b

9^(log₃20) = 3^(log₃20^2) = 400