Please and thank you
FOIL
(2√5+3√2)(2√5-3√2)=
(2√5)(2√5) +(3√2)(2√5)-(2√5)(3√2)-(3√2)(3√2)=
20+6√10-6√10-18=
2
(2√5+3√2)(2√5-3√2)
[2√5] [2√5] + [2√5] [-3√2] + [3√2] [2√5] + [3√2] [-3√2]
4√25 - 6√10 + 6√10 - 9√4
4*5 - 9*2
20 - 18
dude, r u serious?
(a+b)(a-b) = a*a -a*b+b*a - b*b = a*a - b*b
so (2√5+3√2)(2√5-3√2) = 2√5*2√5 - 3√2*3√2 = 20 - 18 = 2
For 10 points, I'll show you how to get it
BEDMAS.
Brackets
Exponents
Division
Multiplication
Addition
Subtracting
Letme guess, is this for school???
no u do it.....
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Verified answer
FOIL
(2√5+3√2)(2√5-3√2)=
(2√5)(2√5) +(3√2)(2√5)-(2√5)(3√2)-(3√2)(3√2)=
20+6√10-6√10-18=
2
(2√5+3√2)(2√5-3√2)
[2√5] [2√5] + [2√5] [-3√2] + [3√2] [2√5] + [3√2] [-3√2]
4√25 - 6√10 + 6√10 - 9√4
4*5 - 9*2
20 - 18
2
dude, r u serious?
(a+b)(a-b) = a*a -a*b+b*a - b*b = a*a - b*b
so (2√5+3√2)(2√5-3√2) = 2√5*2√5 - 3√2*3√2 = 20 - 18 = 2
2
For 10 points, I'll show you how to get it
BEDMAS.
Brackets
Exponents
Division
Multiplication
Addition
Subtracting
Letme guess, is this for school???
no u do it.....