Since it's false when b=0 and a > 0, I have to assume your definition of "naturals" is "positive integers" (there are two different definitions used in mathematics texts).
Under that assumption, note that
a | b
implies that there is some integer k such that
a*k = b.
Also, since a,b are positive, we can divide by a to solve for
k = b/a > 0.
In particular, this shows that k is positive, and the smallest positive integer is 1, so
1 ≤ k
Finally, multiply both sides of this inequality by a > 0 to find
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Since it's false when b=0 and a > 0, I have to assume your definition of "naturals" is "positive integers" (there are two different definitions used in mathematics texts).
Under that assumption, note that
a | b
implies that there is some integer k such that
a*k = b.
Also, since a,b are positive, we can divide by a to solve for
k = b/a > 0.
In particular, this shows that k is positive, and the smallest positive integer is 1, so
1 ≤ k
Finally, multiply both sides of this inequality by a > 0 to find
a ≤ a*k = b.
Suppose that a|b.
So, b = ka for some positive integer k.
Finally, since k is no smaller than 1,
a = 1a ≤ ka = b, as required,
I hope this helps!
if not, then a > b.
Given a|b, then ak = b for some natural k.
a > b = ak
which gives you a false statement. I.e, 1 > k.
even if k = 1, 1 > 1 is still a false statement.