Sendo h(t)=√3t-2, calcule h(2/3), h(4) e h(5) ? o 3t-2 esta todo dentro da raiz.? ajuda
Ola Leticia
h(t) = √(3t - 2)
h(2/3) = √(3*2/3 - 2) = 0
h(4) = √(12 - 2) = √10
h(5) = √13
pronto
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Verified answer
Ola Leticia
h(t) = √(3t - 2)
h(2/3) = √(3*2/3 - 2) = 0
h(4) = √(12 - 2) = √10
h(5) = √13
pronto