Ola Leticia
vou chamar O(x,y) o circuncentro
temos raio R = AO = BO = CO
dAO² = (Ax - Ox)² + (Ay - Oy)² = R²
dAO² = (1 - Ox)² + (4 - Oy)² = R²
dAO² = Ox² - 2Ox + 1 + Oy² - 8Oy + 16 = R²
dAO² = Ox² + Oy² - 2Ox - 8Oy + 17 = R²
dBO² = (Bx - Ox)² + (By - Oy)² = R²
dBO² = (0 - Ox)² + (1 - Oy)² = R²
dBO² = Ox² + 1 + Oy² - 2Oy + 1 = R²
dBO² = Ox² + Oy² - 2Oy + 2 = R²
dCO² = (Cx - Ox)² + (Cy - Oy)² = R²
dCO² = (3 - Ox)² + (1 - Oy)² = R²
dCO² = Ox² - 6Ox + 9 + Oy² - 2Oy + 1 = R²
dCO² = Ox² + Oy² - 6Ox - 2Oy + 10 = R²
Ox² + Oy² - 2Ox - 8Oy + 17 = R²
Ox² + Oy² - 2Oy + 2 = R²
Ox² + Oy² - 6Ox - 2Oy + 10 = R²
2Ox + 8Oy - 17 = Ox² + Oy² - R²
2Oy - 2 = Ox² + Oy² - R²
6Ox + 2Oy - 10 = Ox² + Oy² - R²
2Ox + 8Oy - 17 = 2Oy - 2
2Ox + 6Oy = 15
6Ox + 2Oy - 10 = 2Oy -2
6Ox = 8
Ox = 4/3
8/3 + 6Oy = 15
8 + 18Oy = 45
18Oy = 37
Oy = 37/18
o circuncentro desse triangulo
O(4/3, 37/18)
pronto
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Verified answer
Ola Leticia
vou chamar O(x,y) o circuncentro
temos raio R = AO = BO = CO
dAO² = (Ax - Ox)² + (Ay - Oy)² = R²
dAO² = (1 - Ox)² + (4 - Oy)² = R²
dAO² = Ox² - 2Ox + 1 + Oy² - 8Oy + 16 = R²
dAO² = Ox² + Oy² - 2Ox - 8Oy + 17 = R²
dBO² = (Bx - Ox)² + (By - Oy)² = R²
dBO² = (0 - Ox)² + (1 - Oy)² = R²
dBO² = Ox² + 1 + Oy² - 2Oy + 1 = R²
dBO² = Ox² + Oy² - 2Oy + 2 = R²
dCO² = (Cx - Ox)² + (Cy - Oy)² = R²
dCO² = (3 - Ox)² + (1 - Oy)² = R²
dCO² = Ox² - 6Ox + 9 + Oy² - 2Oy + 1 = R²
dCO² = Ox² + Oy² - 6Ox - 2Oy + 10 = R²
Ox² + Oy² - 2Ox - 8Oy + 17 = R²
Ox² + Oy² - 2Oy + 2 = R²
Ox² + Oy² - 6Ox - 2Oy + 10 = R²
2Ox + 8Oy - 17 = Ox² + Oy² - R²
2Oy - 2 = Ox² + Oy² - R²
6Ox + 2Oy - 10 = Ox² + Oy² - R²
2Ox + 8Oy - 17 = 2Oy - 2
2Ox + 6Oy = 15
6Ox + 2Oy - 10 = 2Oy -2
6Ox = 8
Ox = 4/3
8/3 + 6Oy = 15
8 + 18Oy = 45
18Oy = 37
Oy = 37/18
o circuncentro desse triangulo
O(4/3, 37/18)
pronto