help, help, help!!!
im guessing its 2n+2 but it might be wrong...
Select the recursion formula for 2, 4, 8, 16,…, where a1 =2.
an=(an-1)*2
a2=a1*2-->4=2*2
a3=a2*2-->8=4*2
The next term is 2 times the previous terms
a2 = 2*a1
a3 = 2*a2
etc
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Verified answer
an=(an-1)*2
a2=a1*2-->4=2*2
a3=a2*2-->8=4*2
The next term is 2 times the previous terms
a2 = 2*a1
a3 = 2*a2
etc