Find the sum of the terms in the geometric series -4 + 8 -16 + 32 - … with n = 8.?
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Find the sum of the terms in the geometric series -4 + 8 -16 + 32 - … with n = 8.
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HELP!! HELP!!!
Find the sum of the terms in the geometric series -4 + 8 -16 + 32 - … with n = 8.
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a = -4, r = -2
s(n) = a(1-r^n)/(1-r)
s(8) = -4(1-(-2^8))/(1-(-2))
s(8) = -4(1-256)/(1+2)
s(8) = -4(-255)/3
s(8) = 340