sejam os pontos a e b as extremidades de um segmento e M(2,3) o ponto médio de segmento AB. Sendo A(5,2). As coordenadas do ponto B são:
Mx = (Ax + Bx)/2
Ax + Bx = 2*Mx
Bx = 2*Mx - Ax
Bx = 2*2 - 5 = -1
My = (Ay + By)/2
Ay + By = 2*My
By = 2*My - Ay
By = 2*3 - 2 = 4
A(5,2) e B(-1,4)
pronto
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Mx = (Ax + Bx)/2
Ax + Bx = 2*Mx
Bx = 2*Mx - Ax
Bx = 2*2 - 5 = -1
My = (Ay + By)/2
Ay + By = 2*My
By = 2*My - Ay
By = 2*3 - 2 = 4
A(5,2) e B(-1,4)
pronto