. determine a medida dos lados AB e AC do triângulo.
Ola matheus
A = 30°
B = 45°
C = 105°
sen(A) = 1/2
sen(B) = √2/2
sen(C) = (√2 + √6)/4
Lei dos senos
AB/sen(C) = BC/sen(A) = AC/sen(B)
AB/(√2 + √6)/4 = 10/(1/2) = AC/(√2/2)
4AB/(√2 + √6) = 20
AB = 5*(√2 + √6)
2AC/√2 = 20
AC = 10√2
pronto
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Ola matheus
A = 30°
B = 45°
C = 105°
sen(A) = 1/2
sen(B) = √2/2
sen(C) = (√2 + √6)/4
Lei dos senos
AB/sen(C) = BC/sen(A) = AC/sen(B)
AB/(√2 + √6)/4 = 10/(1/2) = AC/(√2/2)
4AB/(√2 + √6) = 20
AB = 5*(√2 + √6)
2AC/√2 = 20
AC = 10√2
pronto