Ola Matheus
Centro C(6,-3)
distancia
d = ¦2x + 1y - 4¦/√(A² + B²)
d = ¦2*6 - 1*3 - 4¦/√(2² + 1²)
d = ¦12 - 7¦/√5 = 5/√5 = √5
pronto
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Verified answer
Ola Matheus
Centro C(6,-3)
distancia
d = ¦2x + 1y - 4¦/√(A² + B²)
d = ¦2*6 - 1*3 - 4¦/√(2² + 1²)
d = ¦12 - 7¦/√5 = 5/√5 = √5
pronto