Hallar las coordenadas del vértice, foco, las ecuaciones de la directriz y eje y el lado recto.
4x²+48y+12x=159
Hola
Debemos llevar a
(x - Xv)^2 = 4 p (y - Yv)
Vértice en (Xv , Yv)
p : Distancia de vértice a foco y a directriz
Lado recto : doble de abscisa focal = abs(4 p)
4 x^2 + 48 y + 12 x = 159
x^2 + 3 x = -12 y + (159/4)
x^2 + 2*(3/2) x = -12 y + (159/4)
x^2 + 2*(3/2) x + (9/4) = -12 y + (159/4) + (9/4)
(x + (3/2))^2 = -12 y + (168/4) = -12 y + 42
(x + (3/2))^2 = -12 (y - (42/12))
(x + (3/2))^2 = 4*(-3) (y - (7/2))
*************************************
Vértice (-3/2 ; 7/2)
p = -3
Foco ( (-3/2) ; (7/2) + (-3) ) = (-9/2 ; 1/2)
Directriz
y = (-3/2) - (-3) = (-3/2) + (6/2)
y = 3/2
Lado recto
LR = abs(4 p) = 12
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Answers & Comments
Hola
Debemos llevar a
(x - Xv)^2 = 4 p (y - Yv)
Vértice en (Xv , Yv)
p : Distancia de vértice a foco y a directriz
Lado recto : doble de abscisa focal = abs(4 p)
4 x^2 + 48 y + 12 x = 159
x^2 + 3 x = -12 y + (159/4)
x^2 + 2*(3/2) x = -12 y + (159/4)
x^2 + 2*(3/2) x + (9/4) = -12 y + (159/4) + (9/4)
(x + (3/2))^2 = -12 y + (168/4) = -12 y + 42
(x + (3/2))^2 = -12 (y - (42/12))
(x + (3/2))^2 = 4*(-3) (y - (7/2))
*************************************
Vértice (-3/2 ; 7/2)
p = -3
Foco ( (-3/2) ; (7/2) + (-3) ) = (-9/2 ; 1/2)
Directriz
y = (-3/2) - (-3) = (-3/2) + (6/2)
y = 3/2
Lado recto
LR = abs(4 p) = 12