Explain how 4/√2 is equal to 2√2
4/√2 =
4/√2 * √2/√2 =
4√2/2 =
2√2
4/√2
= 2×2/√2
= 2×√2×√2/√2
= 2×√2×1
= 2√2
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4 / √2 = 4√2 / (√2 x √2) = 4√2 / 2 = 2 √2
= 4√2 / √2√2
= 4√2 /2
You can multiply by (1)
( √2/√2) = (1) so this won't change the value
4/√2 (√2/√2)
= 4√2 / (√2*√2)
We know (2√2)*√2 = 2*(√2*√2) = 2*2 = 4 and (4/√2)*√2 = 4 . So
(2√2)*√2 - (4/√2)*√2 = 0
[(2√2) - (4/√2)]*√2 = 0
And we know √2 ≠ 0 so it must be
(2√2) - (4/√2) = 0
That is , 2√2 = 4/√2 .
multiply by [ √2 / √2 ] and then cancel to get rid of the bottom 2
Certainly
You cannot have square roots as the denominator.
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Answers & Comments
4/√2 =
4/√2 * √2/√2 =
4√2/2 =
2√2
4/√2
= 2×2/√2
= 2×√2×√2/√2
= 2×√2×1
= 2√2
-
4 / √2 = 4√2 / (√2 x √2) = 4√2 / 2 = 2 √2
4/√2
= 4√2 / √2√2
= 4√2 /2
= 2√2
You can multiply by (1)
( √2/√2) = (1) so this won't change the value
4/√2 (√2/√2)
= 4√2 / (√2*√2)
= 4√2 /2
= 2√2
We know (2√2)*√2 = 2*(√2*√2) = 2*2 = 4 and (4/√2)*√2 = 4 . So
(2√2)*√2 - (4/√2)*√2 = 0
[(2√2) - (4/√2)]*√2 = 0
And we know √2 ≠ 0 so it must be
(2√2) - (4/√2) = 0
That is , 2√2 = 4/√2 .
multiply by [ √2 / √2 ] and then cancel to get rid of the bottom 2
Certainly
You cannot have square roots as the denominator.