NOTE: we know that √2 is irrational.
This is how I did it. I just want to make sure that if I did it right or not.
Proof by Contrapositive:
Suppose √2 + √n = r, a rational number
Then √n = r - √2
We square both sides
n = (r - √2)²
expand the right hand side
n = r² - 2*r*√2 + 2
therefore, √2 = (n – 2 - r²) / (-2*r)
numerator and denominator are rational, so √2 is rational, which is not true. Therefore √2 + √n is irrational.
if I am wrong, pls provide me with right proof.
Update:one more question...
give an example of a positive irrational number, x, so that √2 + x is rational.
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Answers & Comments
Verified answer
Additional question: x = 2 - sqrt2.
sqrt2 + x = 2 → rational!
Your proof is fine.
For the second question, 2-â2 will work.
Here is another way: Take each digit, x, of â2
and replace it by 9-x. Call the new number n.
Then â2 + n = 9.9999999... = 10, which is rational.
The proof is valid. Well done.
your method is 100% rite. thats how we solved such probs in school too
Yep Yep, totally valid proof.
Nice one.
:)