cos(π/6 − x) = cos(π/6)cosx + sin(π/6)sinx) = [√3cos(x) + sin(x)]/2
sec(π/6 − x) = 1/cos(π/6 − x) = 2/[√3 cos(x) + sin(x)]
It was probably question number 8.
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cos(π/6 − x) = cos(π/6)cosx + sin(π/6)sinx) = [√3cos(x) + sin(x)]/2
sec(π/6 − x) = 1/cos(π/6 − x) = 2/[√3 cos(x) + sin(x)]
It was probably question number 8.