If 20.0 moles of a gas occupy 5.00L at 273°K(0°C), then the pressure of the gas is ----atm.
PV = nRT
P = nRT / V = (20.0 mol) x (0.08205746 L atm/K mol) x (273 K) / (5.00 L) = 89.6 atm
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PV = nRT
P = nRT / V = (20.0 mol) x (0.08205746 L atm/K mol) x (273 K) / (5.00 L) = 89.6 atm