Physics: A soccer ball is kicked with a speed of 9.95m/s at an angle of 35.0∘ above the horizontal.?
A soccer ball is kicked with a speed of 9.95m/s at an angle of 35.0∘ above the horizontal.
If the ball lands at the same level from which it was kicked, how long was it in the air?
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Time in air t = 2vsinΘ/g
t = 2*9.5*sin35°/9.81 = 1.1635s <--------
note:
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if you need to use a more precise value of g, use 9.80665 m/s^2 , which by definition, is "standard gravity" to get ans = 1.1639 s <------
It was 809535176239*sin(7*pi/36)/398574405096
long in the air as about 1.164977719470330279777190 seconds
before landing as implying you are neglecting air resistance.