Verified answer

(√x)+(√x+2)=2

=>√x+√x+2=2

=>√x+√x+2-2=2-2 [substract 2 from both side]

=.√x+√x=0

=>2√x=0

=>√x=0

=>x=0

so x=0

√x+√x+2=2

2√x+2=2

Divide by 2.

√x+1=1

Subtract 1.

√x= 0

Square.

x = 0

The solution is x = 0.

first multiply sqrt x and sqrt x + 2 by 2 to get rid of the sqrt. also do 2^2 to the other side. Now you should have x + x +2 = 2. add the Xs to get 2x+2=2 then subtract 2 from each side. now you have 2x= 0. divide by 2, but u cannot divide by zero, so the answer is No solution. :)

√x + √(x+2) = 2

square both sides:

x + 2√x(x+2) + (x+2) = 4

2x + 2 + 2√(x²+2x) = 4

2√(x²+2x) = 2 - 2x

√(x²+2x) = 1 - x

square both sides:

x²+2x = 1-2x+x²

4x = 1

x = 1/4