Ola rafaela

logx+1(2x² - 5x + 13) = 2

log(2x² - 5x + 13)/log(x + 1) = 2

log(2x² - 5x + 13) = 2*log(x + 1)

log(2x² - 5x + 13) = log(x² + 2x + 1)

2x² - 5x + 13 = x² + 2x + 1

x² - 7x + 12 = 0

P = c/a = 12 (A)

pronto

log [x+1] (2x^2 - 5x + 13) = 2

2x^2 - 5x + 13 =(x+1)²

2x²-5x+13=x²+2x+1

x²-7x+12=0

produto=c/a=12

Letra A