Ola Rafaela
cos(60) = 1/2
tg(45) = 1
sen(45) = √2/2
sen²(5000º) + cos^2 (5000º) = 1
(1/2 + 2)/(1 - √2/2) = (5/2)/(1 - √2)/2 = 5/( 2 - √2) = 5*(2 + √2)/2
E = 5*(2 + √2)/2 + 1 = (12 + 5√2)/2
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Verified answer
Ola Rafaela
cos(60) = 1/2
tg(45) = 1
sen(45) = √2/2
sen²(5000º) + cos^2 (5000º) = 1
(1/2 + 2)/(1 - √2/2) = (5/2)/(1 - √2)/2 = 5/( 2 - √2) = 5*(2 + √2)/2
E = 5*(2 + √2)/2 + 1 = (12 + 5√2)/2
pronto