Momentum » Basketball Player problem?
Here's a basketball problem: A 86.8 kg basketball player is running in the positive direction at 8.4 m/s. She is met head-on by a 106.4 kg player traveling at 6.1 m/s toward her. If the 106.4 kg player is knocked backwards at 3.5 m/s, what is the resulting velocity of the 86.8 kg player?
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Verified answer
m1 = 86.8 kg and u1 = 8.4m/s
m2= 106.4 kg and u2 = -6.1 m/s. and v2 = 3.5 m.s
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86.8*8.4 + 106.4(-6.1) = 86.8 v + 106.4*3.5
Solving
v = 3.37 m/s
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