while y is given, it turns right into a polynomial (x could have better than one answer).. interior the equation given, for any value of x given, y has basically a million value, yet once you supply a value for y, there could be greater that one x's that would grant that value for y.. occasion: y = x^2 if y = 9 is given, x = 3 and x = -3 are the two innovations enable's say that y = 30 we've: 30 = x^2 + x => x^2 + x - 30 = 0 think of of two numbers such that if u multiply them, they supply -30, and in case you upload them, they supply a million 6 and -5 seem to greater healthful the define so the equation turns into ---> (x + 6)(x - 5) = 0 for this to be genuine, x must be equivalent to -6 or 5 so the answer for x is: x = -6 ; x = 5 notice: if u have an equation ax^2 + bx + c and you cant think of of two numbers that multiply to grant c AND upload to grant b, then use the universal formula: x = (-b +/- sqrt(b^2 - 4ac))/2a the +/- potential which you get 2 values for x, one while u use + and the different while u use - stable luck!
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Verified answer
Convert the fractions to decimal.
0.25x - 1.5y = -4
Eliminate either the x or the y. I'll do the y:
0.25 - 1.5y = -4
0.6x +1.5y = 10.8 (multiplied by 30)
.85x = 6.8
x = 8
(1/4)(8) - (3/2)y = -4
2 - (3/2)y = -4
6 = (3/2)y
y = 4
while y is given, it turns right into a polynomial (x could have better than one answer).. interior the equation given, for any value of x given, y has basically a million value, yet once you supply a value for y, there could be greater that one x's that would grant that value for y.. occasion: y = x^2 if y = 9 is given, x = 3 and x = -3 are the two innovations enable's say that y = 30 we've: 30 = x^2 + x => x^2 + x - 30 = 0 think of of two numbers such that if u multiply them, they supply -30, and in case you upload them, they supply a million 6 and -5 seem to greater healthful the define so the equation turns into ---> (x + 6)(x - 5) = 0 for this to be genuine, x must be equivalent to -6 or 5 so the answer for x is: x = -6 ; x = 5 notice: if u have an equation ax^2 + bx + c and you cant think of of two numbers that multiply to grant c AND upload to grant b, then use the universal formula: x = (-b +/- sqrt(b^2 - 4ac))/2a the +/- potential which you get 2 values for x, one while u use + and the different while u use - stable luck!
0.02(1/4x - 3/2y=-4)
1/4(0.02x + 0.05 = 0.36)
x=-8
y=-4