Sendo f(x)=3x-2 e g(x)=-4x+1. Determine:
a) fog(x)
b)gog(x)
vamos la
fog(x) = f(g(x)) = f(-4x+1) = 3(-4x+1) -2 => -12x+3-2 = > -12x+1 okkkkkk
gog(x) = g(g(x)) = g(-4x+1)= -4(-4x+1) +1 => 16x-4+1 => 16x-3 okkkkkk
fog(x) = 3*g(x) - 2 = 3*(-4x + 1) - 2 = -12x + 3 - 2 = -12x + 1
gog(x) = -4*g(x) + 1 = -4*(-4x + 1) + 1 = 16x - 4 + 1 = 16x - 3
pronto
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Verified answer
vamos la
fog(x) = f(g(x)) = f(-4x+1) = 3(-4x+1) -2 => -12x+3-2 = > -12x+1 okkkkkk
gog(x) = g(g(x)) = g(-4x+1)= -4(-4x+1) +1 => 16x-4+1 => 16x-3 okkkkkk
fog(x) = 3*g(x) - 2 = 3*(-4x + 1) - 2 = -12x + 3 - 2 = -12x + 1
gog(x) = -4*g(x) + 1 = -4*(-4x + 1) + 1 = 16x - 4 + 1 = 16x - 3
pronto