log24x-log(1+√x) = 2?
I forget how to deal with the square root! I just need to see it worked out, thanks!
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I forget how to deal with the square root! I just need to see it worked out, thanks!
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Verified answer
log[24x/(1+√x)] = log100
24x = 100+100√x
6x-25 = 25√x
(6x-25)^2 = 625x
36x^2-925x+625 = 0
(36x-25)(x-25) = 0
x = 25 or 25/36 (extraneous)
Answer x = 25