Let y=x^2. Find Δy if x=2 and dx=1?
My professor got 5 but I got 4 what did I do wrong?
Δy = f(3) - f(2) = 3^2 - 2^2 = 5
dy = y'dx = 2xdx = 2*2*1 = 4
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Δy = f(3) - f(2) = 3^2 - 2^2 = 5
dy = y'dx = 2xdx = 2*2*1 = 4