Is this right? Math problem-college algebra. My friend needed help with the √(20x2-20x 5) to factor it out.
i have never factored something with the square root of the entire factor. is this a type-o or do i not know how to do it? if you can solve it, please show me step by step. thanks a million!
This problem is not intended to be solved using the simplist of means.
The factors (if that is all that is needed) of the part within the bracket are: 2 x 2 x 5 x (2 - 5) .
Inside the bracket this gives a negative number = - 3 for which no square root is known, but the imaginary value of square root of -1 or i can be applied. Even so, the only part that comes out of the outside square root is 2, the rest being exactly indeterminate.
0.a million is the finest answer. I in basic terms solved the equation and were given a similar answer. Then I checked it and it grow to be good. You solved the placement good, yet you ought to have checked it incorrect; per chance you distributed incorrectly. replace all the x's with .a million and use a calculator. be particular you distribute good.
Answers & Comments
Verified answer
√(20x² - 20x + 5) =
√[ (5)(4x² - 4x + 1) ] =
√[ (5)(2x -1)² ] =
√(2x - 1)² * √5 =
(2x - 1)√5
This problem is not intended to be solved using the simplist of means.
The factors (if that is all that is needed) of the part within the bracket are: 2 x 2 x 5 x (2 - 5) .
Inside the bracket this gives a negative number = - 3 for which no square root is known, but the imaginary value of square root of -1 or i can be applied. Even so, the only part that comes out of the outside square root is 2, the rest being exactly indeterminate.
0.a million is the finest answer. I in basic terms solved the equation and were given a similar answer. Then I checked it and it grow to be good. You solved the placement good, yet you ought to have checked it incorrect; per chance you distributed incorrectly. replace all the x's with .a million and use a calculator. be particular you distribute good.