In Triangle ABC, AB = CB, m<ABC = 4x – 3, and m<CAB = x – 3. What is m<ACB?
Been trying to figure this out with my brother for a while now and I do not understand it. If anyone has the answer and can explain to me how to work it out I would appreciate it.
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Since AB = CB the triangle is isosceles.
Therefor m<ACB = m<CAB = x – 3
The total of the angles is 180
(4x - 3) + (x - 3) + (x - 3) = 180
Combine like terms
6x - 9 = 180
Add 9 to both sides
6x = 189
Divide both sides by 6
x = 31.5
m<ACB = x – 3
m<ACB = 31.5 - 3
m<ACB = 28.5º
m10232012
the triangle is isosceles , so m<CAB = m<ACB
all three angles together equal 180º ___ 4x - 3 + x - 3 + x - 3 = 180º ___ 6x - 9 = 180º ___ x = 31.5º