In the circuit diagram, R1 = 20.0 Ω, R2 = 15.0 Ω, and R3 = 25.0 Ω; voltage U = 18.00 V.?
a)What is the total equivalent resistance in the unit of Ω?
b). What is the current I in the unit of A through this circuit?
c). What is the electric power in the unit of W for this circuit?
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Answers & Comments
Since the resistors are in series, the total equivalent resistance is the sum of these three numbers.
Req = 20 + 15 + 25 = 60 Ω
To determine the current that flows through these three resistors, use the following equation.
V = I * R
18 = I * 60
T = 18 ÷ 60 = 0.3 amps
To determine the total power, use the following equation.
P = V * I = 18 * 0.3 = 5.4 watts
I hope this is helpful for you.
a) 20+15+25=60
b) I=V/R so I=18/60=3/10=0.3A
c) P=VI=18x0.3=54/10=5.4Watts
Rtot=20+15+25= 60
V=IR
I=V/R= 18/60=.3A
P=I^2 R or IV= 5.4 W
I am getting :
60
0.3
5.4