If y= f[ √(x^2 + 9) ] and f'(5) = -2, find dy/dx when x=4??
Can someone show me full steps on finding slope based on condition??
I started with chain rule, but I dont know what to do with f??
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Can someone show me full steps on finding slope based on condition??
I started with chain rule, but I dont know what to do with f??
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y = f[sqrt(x^2+9)]
take derivative
dy/dx = f'[sqrt(x^2+9)] * [x/(sqrt(x^2+9) ]
f'(5) = -2
dy/dx = -2 * [x/(sqrt(x^2+9)]
plug in x = 4.
dy/dx = -2*[4/(sqrt(16+9)] = -8/[sqrt(25)] = -8/5.