the square root is just on the x, not on the 4
lim x→16 (x-16)/(√x -4)
Multiply numerator and denominator by(√x +4) to get
(x-16)/(√x -4)={(x-16)(√x +4)}/{(√x -4)(√x +4)}
={(x-16)(√x +4)}/{(x -16)} =(√x +4)
Hence
lim x→16 (x-16)/(√x -4)=lim x→16 (√x +4)=(√16 +4) =4+4=8
lim x->16 (x - 16)/(√x - 4) = lim x->16 (√x - 4)(√x + 4)/(√x - 4) = 4 + 4 = 8
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Verified answer
lim x→16 (x-16)/(√x -4)
Multiply numerator and denominator by(√x +4) to get
(x-16)/(√x -4)={(x-16)(√x +4)}/{(√x -4)(√x +4)}
={(x-16)(√x +4)}/{(x -16)} =(√x +4)
Hence
lim x→16 (x-16)/(√x -4)=lim x→16 (√x +4)=(√16 +4) =4+4=8
lim x->16 (x - 16)/(√x - 4) = lim x->16 (√x - 4)(√x + 4)/(√x - 4) = 4 + 4 = 8