If r(x) = 3x − 1 and t(x) = −4x − 1, find (r + t)(7). 9 −9 −49 49 Please help me fast.?
f f(x) = 2x − 4 and g(x) = 1 over 2x − 2, find f[g(−4)].
12
−12
−8
8
If h(x) = x − 1 and j(x) = −4x, find h[j(5)].
−19
−21
−16
−20
If f(x) = −3x − 3 and g(x) = 2x + 1, find f over g(−2).
−3
3
−1
1
If f(x) = 1 over 2x + 3 and g(x) = −4x − 1, find g[f(4)].
21
−21
19
−19
If f(x) = 2x + 1 and g(x) = −2x − 3, find (f + g)(−1).
2
4
−2
−8
If f(x) = 1 over 3x − 2 and g(x) = −2x − 3, find (f • g)(6)
15
−15
0
−17
I know this sounds like a lot but I did as much as i could on my own.
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1. If r(x) = 3x − 1 and t(x) = −4x − 1, find (r + t)(7).
(r+t)(7) = r(7) + t(7) = 3(7)-1 + -4(7) - 1 = 21 - 1 - 28 - 1 = -9
2. If f(x) = 2x − 4 and g(x) = 1 / (2x − 2), find f[g(−4)].
f[g(-4)] = f[1/(2[-4]-2)] = f[1/(-8-2)] = f[1/-10] = 2(-1/10) - 4 = -2/10 - 4 = -1/5 - 4 = -1/5 - 20/5 = -21/5
3. If h(x) = x − 1 and j(x) = −4x, find h[j(5)].
h[j(5)] = h[-4(5)] = h[-20] = (-20) - 1 = -21
4. If f(x) = 2x + 1 and g(x) = −2x − 3, find (f + g)(−1).
(f+g)(-1) = f(-1) + g(-1) = [2(-1) + 1] + [-2(-1) - 3] = -2 + 1 + 2 - 3 = -2
5. If f(x) = 1 / (3x − 2) and g(x) = −2x − 3, find (f • g)(6).
(f • g)(6) = f(6) * g(6) = 1/(3[6]-2) * (-2[6] - 3) = 1/(18-2) * (-12 - 3) = 1/16 * -15 = -15/16
Questions 2 and 5 (the ones with fractions in the definitions) do not yield integer solutions from your lists of answers. You should check your source material to see where the brackets are and reevaluate, using the principles show here.