also, what is f'(-3)?
So
f(-3)=integral from -3 to 10 t^3 dt = t^4/4 between 10 and -3
The value=1/4(10^4-(-3)^4)=1/4(10,000-81)=1/4(9919)
f'(x)= -x^3
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
So
f(-3)=integral from -3 to 10 t^3 dt = t^4/4 between 10 and -3
The value=1/4(10^4-(-3)^4)=1/4(10,000-81)=1/4(9919)
f'(x)= -x^3