If 2x^2+2x+xy=1 and y(1)=−3, find y′(1) by implicit differentiation.?
If 2x^2+2x+xy=1 and y(1)=−3, find y′(1) by implicit differentiation.
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If 2x^2+2x+xy=1 and y(1)=−3, find y′(1) by implicit differentiation.
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Differentiating implicitly:
4x + 2 + xy' + y = 0
At the point (1, -3):
4 + 2 + y' - 3 = 0
y' (1) = -3