To get started, get the absolute value on one side and everything else on the other. To do this, subtract 3 from each side in the inequality |5 – 3x| + 3 ≤ 7.
Now we have
|5 – 3x| ≤ 4
This means that 5 – 3x ≤ 4 and 5 – 3x ≥ - 4
Solve both inequalities.
5 – 3x ≤ 4
Subtract 5 from each side
-3x ≤ -1
Divide each side by -3
x ≥ 1/3 (notice that ≤ became ≥ which happens when dividing by a negative number)
5 – 3x ≥ - 4
Subtract 5 from each side
-3x ≥ - 9
Divide each side by -3
x ≤ 3 (notice that the inquality flipped again because we divided by a negative)
So the solutions are x ≥ 1/3 and x ≤ 3 which is the same as 1/3 ≤ x ≤ 3
Answers & Comments
Verified answer
To get started, get the absolute value on one side and everything else on the other. To do this, subtract 3 from each side in the inequality |5 – 3x| + 3 ≤ 7.
Now we have
|5 – 3x| ≤ 4
This means that 5 – 3x ≤ 4 and 5 – 3x ≥ - 4
Solve both inequalities.
5 – 3x ≤ 4
Subtract 5 from each side
-3x ≤ -1
Divide each side by -3
x ≥ 1/3 (notice that ≤ became ≥ which happens when dividing by a negative number)
5 – 3x ≥ - 4
Subtract 5 from each side
-3x ≥ - 9
Divide each side by -3
x ≤ 3 (notice that the inquality flipped again because we divided by a negative)
So the solutions are x ≥ 1/3 and x ≤ 3 which is the same as 1/3 ≤ x ≤ 3
|5-3x|<4
5-3x<4 -3x<-1 x<1/3
5-3x>-4 -3x>-9 x>3
The first solution is right