i've been working on this one for a long time and just can't find an answer. if you could tell me step by step how it can be done, that would be great.
This is the difference of two cubes which has its own special pattern: a^3 - b^3 = (a-b)(a^2 + ab + b^2)
In this instance, your "a" is (2a) and your "b" is 3. Therefore, it looks like this:
(2a)^3 - (3)^3 = (2a-3)(4a^2 + 6a + 9)
that's it! :)
I'll get you started...Look at each term separately first.
Does 8 have a cube root? What can you cube to get 8? How about 2 * 2 * 2?
a^3 should be obvious
What about 27? What factor can you cube to get 27?
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This is the difference of two cubes which has its own special pattern: a^3 - b^3 = (a-b)(a^2 + ab + b^2)
In this instance, your "a" is (2a) and your "b" is 3. Therefore, it looks like this:
(2a)^3 - (3)^3 = (2a-3)(4a^2 + 6a + 9)
that's it! :)
I'll get you started...Look at each term separately first.
Does 8 have a cube root? What can you cube to get 8? How about 2 * 2 * 2?
a^3 should be obvious
What about 27? What factor can you cube to get 27?