I BET YOU CANT SOLVE THIS PHYSICS QUESTION: A horse starts from rest and runs in a straight line 29° N of W?
A wild horse starts from rest and runs in a straight line 29° north of west. After 26 s of running in this direction, the horse has a speed of 18 m/s.
(a) What is the magnitude of the horse's average acceleration?
(b) Assuming that north and east are the positive directions, find the component of the horse's acceleration that points along the north-south line.
(c) Find the component of the horse's acceleration that points along the east-west line.
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Verified answer
Easy trig
A = change in velocity / time = 18 m/s / 26 s = 0.69 m/s^2
Draw the picture on graph paper: 69 units up and to the left then a horizontal line through the end of the first line
Angle = 29
Y axis = adjacent side
horizontal line paralel to x avis that touches the acceleration line is the opposite side.
Do the Trig
cos 29 = y/0.69 = 0.60 m/s^2 Y component Since it is up it is +
sin 29 = x/0.69 = 0.33 m/s^2 X component Since it is Left it is =
X component = - 0.33 m/s^2