3 + x - 8x = 0
3 = 7x
x = 3/7
However you MAY have meant:-
3 + √(x² - 8x) = 0
√(x² - 8x) = - 3
x² - 8x = 9
x² - 8x - 9 = 0
(x - 9)(x + 1) = 0
x = 9 , x = - 1
Conclusion
MUST USE BRACKETS!!!
is x^2 -8x under the radical sign?
If it's not, then:
3 + sqrt(x^2) - 8x = 0
3 + x - 8x = 0 : taking square root
3 - 7x = 0 : combining x
x = 3/7 : solve for x
If it is, then
3 + sqrt(x^2 - 8x) = 0
sqrt(x^2 - 8x) = -3 : bring 3 over
sqrt(x^2 - 8x)^2 = (-3)^2 : square both sides
x^2 - 8x = 9
x^2 - 8x - 9 = 0
x = ? : use quadratic formula
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Answers & Comments
Verified answer
3 + x - 8x = 0
3 = 7x
x = 3/7
However you MAY have meant:-
3 + √(x² - 8x) = 0
√(x² - 8x) = - 3
x² - 8x = 9
x² - 8x - 9 = 0
(x - 9)(x + 1) = 0
x = 9 , x = - 1
Conclusion
MUST USE BRACKETS!!!
is x^2 -8x under the radical sign?
If it's not, then:
3 + sqrt(x^2) - 8x = 0
3 + x - 8x = 0 : taking square root
3 - 7x = 0 : combining x
x = 3/7 : solve for x
If it is, then
3 + sqrt(x^2 - 8x) = 0
sqrt(x^2 - 8x) = -3 : bring 3 over
sqrt(x^2 - 8x)^2 = (-3)^2 : square both sides
x^2 - 8x = 9
x^2 - 8x - 9 = 0
x = ? : use quadratic formula