Verified answer

first multiply last term with first term

in rough work

you'll get 6x² * 3=18x²

now break into two terms 18x² in such a way that it comes 7x when added/subtracted

it is 9x -2x

now in eqn.

6x²+7x-3=0

7x can be replaced by 9x -2x so the eqn. becomes:

6x²+9x -2x -3=0

taking commons 3x and -1

3x(2x+3) -1(2x+3)=0

again taking (2x+3) common

eqn. becomes

(2x+3)(3x-1)=0

for

(2x+3)=

x=-3/2

for (3x-1)=0

x=1/3

6x²+7x-3=0

First, factor the above eqn.

it would become:

(3x+ 1)(2x- 3)=0

Then:

3x + 1 = 0 2x - 3 = 0

3x = -1 2x= 3

Answers: x = -1/3 x= 2/3

This is how i think u would go about doing it...its possible that the final answer may not b simple enough though.

1.add 3 to both sides (this gets rid of the 3 on the left side) so now u have 6x(squared)+7x=3

2.group the left side. x(6x+7)=3

3. divide both sides by (6x+7) (this gets rid of that part on the left hand side) so now you have, what I believe, is the final answer..... x=3/(6x=7)

btw the / in the last bit means over or divided by.

hope this helps :)

pls let me know if you have any questions

Use delta formula:b^2-4ac»»»»49+72=121

now use this formula:(-b+-(radical delta))/2a

and u have 2 answers

1) -3/2

2) 1/3

:-)

6x^2+7x-3=0

6x^2+9x-2x-3=0

3x(2x+3)-1(2x+3)=0

(3x-1)(2x+3)=0

3x-1=0 or 2x+3=0

x=1/3 or x=-3/2

The root're 1/3 and -3/2.

( 3x - 1 ) ( 2x + 3 ) = 0

x = 1/3 , x = - 3/2

(3x-1)(2x+3)=0

x = 1/3 or -3/2

if quadratic in form: ax² + bx + c = 0, use quadratic formula.

quadratic formula: x = (-b ± √(b² - 4ac)) / 2a

x = (-7 ± √(49 + 72)) / 12 = (-7 ± 11) / 12

x = (-7 + 11) / 12 = 1/3

x = (-7 - 11) / 12 = -3/2

6x²+7x-3=0

(3x+1)(2x-3)=0

3x+1=0...............2x-3=0

3x=-1..................2x=3

x=-1/3.................x=3/2