Verified answer

Use spaces so Y!A won't truncate expressions;

use grouping because "√" doesn't have a vinculum:

(2x² + 5)(9 + 1/(2√(x))) + (9x + √(x))(4x)

18x² + x²/√(x) + 45 + 5/(2√(x)) + 18x² + 4x√(x)

54x² + x²/√(x) + 4x√(x) + 45 + 5/(2√(x))

54x² + x²√(x)/x + 4x√(x) + 45 + 5/(2√(x))

54x² + x√(x) + 4x√(x) + 45 + 5/(2√(x))

54x² + 5x√(x) + 45 + 5/(2√x)

or

54x² + 5x^(3/2) + 45 + 5/(2√x)

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The trick is to discover 2 numbers which you would be able to multiply to get 8 (2x4) and upload to get 9. The numbers 8 and a million might desire to are evoked. then you definately replace those numbers into the equation in selection to 9x. as a result the expression will become 2x^2 + 9x + 4 2x^2 + 8x + x + 4 you will possibly desire to then take out person-friendly aspects 2x(x+4) + a million(x+4) (increasing this expression might desire to offer you the unique expression) the suitable answer is (2x +a million)(x+4)