We require real solutions and there the input inside the principal square root function cannit be negative. So x^2 - 9 has to be greater than 0.
That gives u x>3 and x< (-3)
Its x <=-3 and
x>=3.
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We require real solutions and there the input inside the principal square root function cannit be negative. So x^2 - 9 has to be greater than 0.
That gives u x>3 and x< (-3)
Its x <=-3 and
x>=3.