I'm studying time dilation, doing the math involved so i understand as i go along. Being the time it is however, i am flunking my simple mathematics. Can someone solve this equation for me for Δt', and tell me the steps while you do, so I can write them down?
Δt' = (2*√(((1/2)*v*Δt')² + L²))/c
That reads- Change in t' is equal to two times the squart root of one-half times v times the change for t' squared plus L squared all over c
I just need to solve for Δt'. Leaving all the variables in. Can someone tell me the steps- the answer should come out to be:
Δt' = (2L/c)/√(1-v²/c²)
That's read - Change of t' is equal to 2 times L divided by c all over the square root of 1 minus v squared over c squared.
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Verified answer
(What a mess!)
Let's call x = Δt'
x = (2*√(((1/2)*v*x)² + L²)) / c
cx = 2*√( ((1/2)*v*x)² + L² )
cx = 2*√( v²x²/4 + L² )
c²x² = 4 *( v²x²/4 + L² ) = v²x² + 4L²
c²x² - v²x² = 4L² = x²(c² - v²)
x² = 4L² / (c² - v²) = 4L²/c²/1-v²/c²
x = (2L/c)/√(1-v²/c²)