How much heat must be absorbed by a 20.0g sample of water to raise its temperature from 29.0∘C to 43.0∘C? (For water, Cs=4.18J/g∘C.)
Can some please explain how to solve this problem.
Q = m C delta-T
= (20 g)(4.18 J/g K)(14 K)
= 1170 J
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Q = m C delta-T
= (20 g)(4.18 J/g K)(14 K)
= 1170 J