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here is a similar problem, change the numbers

What is the energy needed to heat 1 kg of ice at –20ºC to steam at 150ºC

Ans:

specific heat of water is 4.186 kJ/kgC

specific heat of ice is 2.06 kJ/kgC

specific heat of steam is 2.1 kJ/kgK

heat of fusion of ice is 334 kJ/kg

heat of vaporization of water is 2256 kJ/kg

5 parts to this problem, add them up to get the total

to warm ice to 0C

E1 = 2.06 kJ/kgC x 1 kg x 20C

to melt ice

E2 = 334 kJ/kg x 1 kg

to warm water from 0C to 100C

E3 = 4.186 kJ/kgC x 1 kg x 100C

to boil water

E4 = 2256 kJ/kg x 1 kg

to heat steam from 100C to 150C

E5 = 2.1 kJ/kgC x 1 kg x (150–100)C

E = E1 + E2 + E3 + E4 + E5