How much current is drawn from an ideal 12.8V battery (no significant internal resistance) when a 18.0 Ω resistor is connected across its terminals?
Please explain
Update:didnt realize all there was to it was divide. THANKS ALOT!
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Verified answer
12.8 / 18 = 0.71A
seem any voltmeter measures the voltage for the time of its terminals .despite if it is a suited voltmeter then it won't drown any modern-day .and the voltage ac pass its terminals is the emf of the cellular.(there's a distinction between the emf and the voltage of the cellular , the voltage is the emf minus the multiplication of the present with the aid of the battery and the interior resistance of the battery. the resistance of the suited battery is 0. for non suited circumstances replace the battery with the an suited battery with a suited battery and the interior resistance in sequence . the non suited voltmeter must be replaced with the voltmeter resistance in parallel with an suited voltmeter. so the suited voltmeter will diploma the voltage around the interior resistance of the voltmeter.and it is the analyzing of the voltmeter . the emf of the cellular is a well-known one ,it is value relies upon on the concentration of the electrolyte ,nature of the electrolyte and the area between the electrodes and the character of the electodes. while cellular gets used the concentration of the electrolytes decreases, and and voltage decreases however the emf maintains to be the comparable because of the fact it is a well-known one.the area between the electrodes doest get altered in using the cellular.
Use Ohm's law. I=E/R.