Verified answer

3.34 mol KMnO4 * ( 4 mol O / 1 mol KMnO4)

48.3 mol CO2 * (2 mol O/ 1 mol CO2)

2.28X10^-2 mol CuSO4·5H2O * (9 mol O/ 1 mol CuSO4·5H2O)

I'll do the first one and you should be able to get the others.

1 mole of KMnO4 contains 4 moles of oxygen

4(3.34) = 13.36 moles of oxygen