NiCl2 + 2 NaOH → Ni(OH)2 + 2 NaCl
(33.0 mL) x (0.350 M NiCl2) x (2 mol NaOH / 1 mol NiCl2) / (0.200 M NaOH) = 115.5 mL NaOH
[Adjust the number of significant digits as you see fit.]
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NiCl2 + 2 NaOH → Ni(OH)2 + 2 NaCl
(33.0 mL) x (0.350 M NiCl2) x (2 mol NaOH / 1 mol NiCl2) / (0.200 M NaOH) = 115.5 mL NaOH
[Adjust the number of significant digits as you see fit.]