How many liters of H2 would be formed at 642 mm Hg and 16 ∘C if 30.0 g of zinc was allowed to react?
Update:
Hydrogen gas can be prepared by reaction of zinc metal with aqueous HCl:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
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Verified answer
Zn + 2 HCl → ZnCl2 + H2
(30.0 g Zn) / (65.380 g Zn/mol) x (1 mol H2 / 1 mol Zn) = 0.458856 mol H2
V = nRT / P = (0.458856 mol) x (62.36367 L mmHg/K mol) x (16 + 273) K /
(642 mm Hg) = 12.9 L H2
react with WHAT?
NONE. Zinc is an ELEMENT and doesn't contain Hydrogen. Without another substance, no reaction would occur at ANY temperature OR pressure. In any case, temperature and pressure effect the SPEED of a reaction, not the amount of product.