Looks like I've forgotten some algebra skills. :p Any help?
√(72x^3)
Isolate values of which you can take the square root:
√(72x^3) = √(36(2)(x^2)(x))
Then take the square root of those values, leaving the remaining values under the radical sign:
6x√(2x)
2^3/2 * 3 * x^3/2
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Isolate values of which you can take the square root:
√(72x^3) = √(36(2)(x^2)(x))
Then take the square root of those values, leaving the remaining values under the radical sign:
6x√(2x)
2^3/2 * 3 * x^3/2