How do you solve Ix+1I + Ix-2I ≤ 2? Please show all work and steps and explain while doing this so I can understand.
THANKS SO MUCH TO EVERYONE WHO ANSWERS!
You'll get 10 points within the next 4 hours.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Ix+1I + Ix-2I ≤ 2
lx+1l + lx-2l = x+x-1
x+x-1 < 2, and therefore x must be 1.49999 repeating, or less.
People that answer in the simple ways as yes or no, or like u said just a few words are not thinking things out. They just want points. I am a thinker and only answer things that i might have an answer for. This one...well maybe 3. You have to think about the question and give an answer that people may be helped. I am sure I will get a lot of thumbs down, but that is not what it is all about. Plus it takes me awhile to type. I am not the fastest person out there. Hope you like what I just said. I like sharing my inner thoughts with others
|x+1| + |x-2| ≤2
|x-1| ≤ 2- |x+1| |x+1| is x+1
|x-1| ≤ 2-x+1
|x-1| ≤ 3-x |x-1| is x+1
x+1 ≤ 3-x
2x ≤ 2
x ≤ 1
shiriz has it right